What is the smallest number that must be added to 763 to make it divisible by 9?
- A.1
- B.2 ✓
- C.3
- D.4
Explanation: 763 ÷ 9 = 84 remainder 7, so 763 is 7 more than a multiple of 9 — adding 2 more reaches the next multiple: 765 = 9 × 85.
Class 6 IMO Mathematics Olympiad practice · Number Sense · Factors, Multiples & Primes
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